the limit of x -> -1 at (6x^2 +5x−1)

y = x^13

dy/dx =

x(t)=2t - 2 − 3t + 5
a(t) when t = 1
a(1) =

Definite Integral from 6 to 1 of 2dx

If t g(x) = x^3+1
Find the The absolute minimum value of the closed interval -2 < x < 3 occuring at which x value

the limit of x -> 2 at (x^3 - 2x^2) / (x^2 - 4)

The value of d/dx (x^4 - 4x^2 - 10x) at x = 3

v(t)=t^3 − 3t^2 − 8t + 3
v(t) at t = 4
v(4) =

Integrate 3x(6−x^2)dx

f(x) = x^3 +9x^2+13x, c is the number satisfying the MVT for f on the interval -7 < x < -1

Find C

the limit of x -> -3 at (x^3 + x^2 - 6x) / (x^2 + 3x)

(x^3 - 7x + 2) / (x - 2)
dy/dx at x = 4 is...

x(t)=t - 2 −10t
v(t) at t = 4
v(4) =

∫(4e^x − x^5 )

y^2 − x^2y + 3x^3 = 4

the limit of pi/3 at sec(x)

cos(5x^2 - x)
dy/dx =

x(t)=t - 2 −10t
v(t) at t = 4
Particle motion moving to the...

∫x^3+4x^2dx

Find the average value of -x^2 + 3 on the interval [0, 6]

the limit of pi/2 at sec(x)

Find d/dx of (e^x sin x)

x(t)=t^3−3t^2+7t−6
a(t) at t = 3
a(3) =

∫1 / x^2 + 8x + 52

Derivative of 1